can you please find the roots of this equation.. thanks.. pease include the step by step solution....
180^2 (y^2 + 4y + 69)^3 = 100^2 (y^2 - 8y + 29)^3
here's how it reads....
one hundred eighty two squared times open quantity of y squared plus four y plus sixty nineclose quantity cube equals one hundred squared open quantity y squared minus eight y plus 29 close quantity cube.. the expression y^2+4y+69 and y^2 -8y +29 are the only ones cubed.. the 180 and 100 are squared... got it????? thanks
2007-03-11 00:50:57 · 3 answers · asked by joan the great 3 in Science & Mathematics ➔ Mathematics
sorry, its just one hundred eighty.. not one hundred eight two.. my mistake
2007-03-11 01:09:47 · update #1
Please correct your text. The arithmetic expression starts:
'one hundred eighty squared', but the text starts 'one hundred eighty two squared'.
2007-03-11 01:06:15 · answer #1 · answered by Anonymous · 0⤊ 0⤋
the numbers 180^2 and 100^2
aren't suitable to solve the equation without calculator.
Please check these numbers.
2007-03-11 09:12:38 · answer #2 · answered by iyiogrenci 6 · 0⤊ 0⤋
take cube root on both sides and solve the thus obtained quadratic equation in y
2007-03-11 09:02:58 · answer #3 · answered by cyberbob 1 · 0⤊ 0⤋