2007-03-10 23:20:54 · 7 answers · asked by Pat J 1 in Science & Mathematics ➔ Mathematics
9a² - 64b²
(3a - 8b)(3x + 8b)
- - - - - - - - - - -s-
2007-03-11 03:48:14 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
^2 (square)
9a^2 - 64b^2 (9 = 3^2, 64 = 8^2)
= 3^2a^2 - 8^2b^2
= (3a - 8b)(3a+8b)
the rule says a^2 - b^2 = (a - b)(a + b)
2007-03-11 09:46:36 · answer #2 · answered by Stephanie K 2 · 0⤊ 0⤋
I dont know what you want from your problem... but if you mean 9a^2 - 64b^2 and you teacher want you to factor it then this will help:
9a^2 - 64b^2 = (3a + 8b)(3a - 8b)
2007-03-11 07:32:34 · answer #3 · answered by shadcode 2 · 0⤊ 0⤋
Sweetie, it's 4 in the morning. Go to sleep. I'll tell you the answer tomorrow. Promise.
2007-03-11 07:24:02 · answer #4 · answered by Debi in LA 5 · 0⤊ 0⤋
9a^2-64b^2=(3a-8b)(3a+8b)
2007-03-11 07:25:46 · answer #5 · answered by iyiogrenci 6 · 0⤊ 0⤋
(3a-8b)(3a+8b)
2007-03-11 07:35:22 · answer #6 · answered by neeraj l 2 · 0⤊ 0⤋
(3a)^2-(8b)^2
(3a-8b)(3a+8b)
2007-03-11 07:26:00 · answer #7 · answered by shilpu 2 · 0⤊ 0⤋