Write an equation?

Question

Write equation of line that goes through the point (– 2, 3) parallel to the line: x + y = 5

Answer 1

x+y=5
y=-x+5
so slope=-1
since lines r \\ so slopes r same
equation will be
y-3=(x+2)-1
y-3=-x-2
=y+x-1

Answer 2

y = - x + 5 so m = - 1
Required line has m = - 1 and passes thro` (- 2, 3)
Equation is given by:-
y - 3 = - 1 (x + 2)
y - 3 = - x - 2
y = - x + 1

Answer 3

x+y=5
y=5-x
this is line equation , parallel so slope is the same , and is -1
your line y=-x + a
point (-x,3) is on the line , place it into equation , you get a=1
y=-x+1

Answer 4

basically you need a line with gradient -1 that goes through
(-2,3)
the eq is,
y - 3 = (-1)(x+2)
=> x+y = 1

Answer 5

since the line is parallel thus they have equal slopes thus the slope of the line,m is -1 (using slope = -coeff of x/coeff of y) and u hv the formula (y-y') = m(x- x')... here y' = 3 and x' = -2, so u hv the eqn as x + y=1...........best of luck for ur math....

Answer 6

ya, miinii got it rite...
the -2 is referring to the x and 3 is referring to the y.
since they are parallel, they must have the same gradient..

Answer 7

slope = (y-yo)/(x-xo)
paralel line is y=-x+5 ,,slope m=-1,,,and
-1=(y-3)/(x-(-2))
-1=(y-3)/x+2
-x-2=y-3
-x-2+3=y,,,,,,,,,,,,-x+1=y,,.
y=-x+1