Answer pls
2007-03-10 19:46:57 · 3 answers · asked by Chester1031 1 in Science & Mathematics ➔ Mathematics
36 = 2² × 3² × (-1)² × 1²
36 × 1 × 1
36 × (-1) × (-1)
(-36) × (-1) × 1
18 × 2 × 1
18 × (-2) × (-1)
(-18) × (-2) × 1
(-18) × 2 × (-1)
12 × 3 × 1
12 × (-3) × (-1)
(-12) × (-3) × 1
(-12) × 3 × (-1)
9 × 4 × 1
9 × (-4) × (-1)
(-9) × (-4) × 1
(-9) × 4 × (-1)
9 × 2 × 2
9 × (-2) × (-2)
(-9) × (-2) × 2
6 × 6 × 1
6 × (-6) × (-1)
(-6) × (-6) × 1
6 × 3 × 2
6 × (-3) × (-2)
(-6) × 3 × (-2)
(-6) × (-3) × 2
4 × 3 × 3
4 × (-3) × (-3)
(-4) × (-3) × 3
I counted 28.. If you don't want to include 1 and -1 as factors then there are only three
9 × 2 × 2
6 × 3 × 2
4 × 3 × 3
2007-03-10 19:57:03 · answer #1 · answered by ........ 5 · 1⤊ 0⤋
36 = (2)²(3)²
If 1 can be a factor and if negative integers can be factors, then there can more combinations possible:
Ex. 1(-2)²(-3)² = 36.
Ex. 2(3)(6), (1)(4)(9), (2)(2)(9)...
2007-03-11 05:10:31 · answer #2 · answered by S. B. 6 · 0⤊ 0⤋
The key point is that the third factor is determined by the first two.
Beyond that -- your question was cut off, you didn't say if they could be negative, and while it's obvious you meant for them to be integers you didn't actually say that.
2007-03-11 13:06:59 · answer #3 · answered by Curt Monash 7 · 0⤊ 0⤋