system of equations?

Question

how would you solve this one?
1/4x+1/4y=-1
x-y=-2

Answer 1

1/4x + 1/4y = - 1- - - - - - Equation 1
x - y = - 2- - - - - - - -- - -- -Equation 2
- - - - - - - - -

Convert equation 1 to standard form

1/4x + 1/4y = - 1

4(1/4x) + 4(1/4y) = - 4(1)

x + y = - 4. . . .standard form equation 1

- - - - - - - - -

x + y = - 4
x - y = - 2
- - - - - - - -
2x = - 6

2x / 2 = - 6 / 2

x = - 6/ 2

x = - 3

Insert the x value into stndard form equation 1
- - - - - - - - - - - - - - - - - - - - - - - --

x + y = - 4

-3 + y = - 4

- 3 + y + 3 = - 4 + 3

y = - 1

Insert the y value into standard form equation 1
- - - - - - - - - - - - - - - - - - - - - - - - -

Check for standard form equation 1

x + y = - 4

- 3 + (- 1) = - 4

-3 -1 = - 4

- 4 = - 4

- - - - - - -

Check for equation 2

x - y = - 2

- 3 - ( - 1) = - 2

- 3 + 1 = - 2

- 2 = - 2

- - - - - - -

The solution set { -3, -1 }

- - - - - - -- - - -s-

Answer 2

Please note that 1/4x does not equal x/4 but I think you may mean x/4?

x/4 + y/4 = - 1
x - y = - 2

x + y = - 4
x - y = - 2------- Add these equations
2x = - 6
x = - 3
Now x + y = - 4
- 3 + y = - 4
y = - 1
x = - 3, y = - 1

Answer 3

1/4x+1/4y=-1
x-y=-2

4(1/4x+1/4y)=-1*4
x+y=-4
x-y=-2
______
2x = -6

x = -3

x-y=-2
-3-y=-2
3+y=2

y = -1

Answer 4

1/4x+1/4y=-1
x-y=-2

(x + y = -4
(x - y = -2
-------------
2x = -6
x = -3

x - y = -2
-3 - y = -2
-y = -2 + 3
-y = 1
y = -1
Solution: (-3, -1)

Answer 5

1/4x+1/4y=-1

multiply both sides by 4xy

y+x=-4xy

x-y=2

x=y+2

y+y+2=-4y(y+2)

2y+2=-4(y²+2y)

2(y+1)=-4(y²+2y)

y+1=-2y²-4y

2y²+5y+1=0

a=2, b=5, c=1

x={-b±√[b²-4ac]}/2a

x={-5±√[5²-4(2)(1)}/2(2)

x={-5±√(17)}/4

x={-5+√(17)}/4 or {-5-√(17)}/4

y=x-2

y={[-5±√(17)]/4} -2

y={[-5±√(17)]/4} -8/4

y=[-13±√(17)]/4

y=(-13+√17)/4 or (-13-√17)/4

Answer 6

:) or :(
mathhh