Find the slope intercept of the equation of the line that is parallel to the graph of........ 3x-4y=8 and passes through (2,11).
How do I even start this....do I plug in a number for x in the equation and solve for y? Like if I let x =2 then I figured that y= -1/2. Am I on the right track?
Thanks, if you can help.
2007-03-10 17:27:15 · 4 answers · asked by Boo Radley 4 in Science & Mathematics ➔ Mathematics
when the unknown equation is parallel to the original equation, then the slopes are the same.
3x-4y=8
-4y=-3x+8
y=3/4x-2
slope:m=3/4
point (2,11)
y=mx+b
y=3/4x+b
11=2(3/4)+b
11=3/2+b
b=9 1/2
y=3/4x+9 1/2
2007-03-10 17:32:12 · answer #1 · answered by Winnie 3 · 0⤊ 0⤋
a line that's parallel to the given equation has the form:
3x - 4y = 4b, therefore, the line that goes through 2,11 is:
3(2) - 4(11) = 4b, so b = -38/4 = -19/2
so the equation is y = 3/4x +19/2
2007-03-11 01:36:57 · answer #2 · answered by arbiter007 6 · 0⤊ 0⤋
3x-4y=8
-4y=-3x+8
y=3x/4-2
the slope is 3/4 all parallel lines have the same slope.
y=3x/4+b contains (2,11)
11=3*2/4+b
11=3/2+b
9.5=b=19/2
y=3x/4+19/2
2007-03-11 01:38:43 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
3x-4y=8
-4y=-3x+8
y=3/4x-2
slope:m=3/4
point (2,11)
y=mx+b
y=3/4x+b
11=2(3/4)+b
11=3/2+b
b=9 1/2
y=3/4x+9 1/2
when the equation of the line is perpendicular, get the negative reciprocal of the slope
2007-03-11 01:36:29 · answer #4 · answered by lance_nhoj 2 · 0⤊ 1⤋