graph linear inequalities?

Question

x +y=<4
y>_ 2x-4

Answer 1

Here's how to do it.

Graph the boundary line ( the inequality as though it were and equation). It will be a solid line if it has the " or equals" sign and dashed otherwise.

The next step is to determine which side you shade. Pick a point on one side of the line and substitute it into the inequality. If it makes the inequality true, then shade the side of the line the test point was on. If it makes it false, shade the other side.

If you are dealing with a system of two inequalities or more, just graph both on the same coordinate plane and see where the shaded regions are in common. That is your solution area.

Answer 2

x + y <= 4
y >= 2x + 4

First, put both of these *like* the form y = mx + b (except it's inequalities we're dealing with)

y <= -x + 4
y >= 2x + 4

Now, graph the corresponding inequalities y = -x + 4 and
y = 2x + 4 as _solid_ lines.

After graphing these lines, we're either going to shade one side of the line or the other. To determine which side, all we have to do is plug in x = 0 and y = 0 for both inequalities; if we get a true statement, shade part of the line that includes (0,0). If false, shade the part of the line that does NOT include (0,0).

The intersection of the shading is the solution set.

Answer 3

if you want to email me, I can show you....