(9x^3 + 12x^2 - 20x - 16) / (3x - 4)
Write answer in the form Q(x) + r(x)/3x-4, where q(x) is the quotient and r(x) is the remainder of the division
2007-03-10 14:51:44 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(9x^3+12x^2-20x-160/(3x-4)
={3x^2(3x-4)+8x(3x-4)+4(3x-4)}/(3x-4)
=(3x-4)(3x^2+8x+4)/(3x-4)
=3x^2+8x+4
2007-03-10 15:12:08 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
Both of the people above me aren't quite correct, but the second answer is closer. You can break down the numerator into (3x -4)(3x^2+8x+4), and then into (3x-4)(3x+2)(x+2). The (3x-4) is in both the numerator and denominator so "cancel out", leaving (3x+2)(x+2). I don't know if this is your final answer or not, but it's a step further than answered so far.
2007-03-10 15:07:03 · answer #2 · answered by Wanderer 4 · 0⤊ 0⤋
using synthetic division, i divided the polynomial by 4/3 and got 9x^2 + 24x + 12.
it has no remainder which means that 4/3 is a solution to the equation.
2007-03-10 15:01:01 · answer #3 · answered by Newbody 4 · 0⤊ 0⤋
(3x^2+8x+4)+0/(3x-4)
2007-03-10 15:04:20 · answer #4 · answered by dcl 3 · 0⤊ 0⤋