-4x+y=-11
2x-3y= 5
2007-03-10 14:07:35 · 8 answers · asked by Michele N 1 in Science & Mathematics ➔ Mathematics
multiple the second by 2. to get 4x-6y=10 add this to the first
to get -5y=-1, y=1/5
putting y into equation 1 and solving we get
-4x+1/5=-11, -4x=-56/5; x=56/20
2007-03-10 14:15:29 · answer #1 · answered by Rob M 4 · 0⤊ 0⤋
Y= -1/5
2007-03-10 14:15:29 · answer #2 · answered by penelopejanepitstop 5 · 0⤊ 0⤋
Solve system of linear equations?
-4x+y=-11 <-- Eq 1
2x-3y= 5 <--- Eq 2
Multiply Eq 2 by 2 getting:
4x-6y+10 <--- Eq3
Now add Eq 3 and Eq 1 getting:
-5y = -1
y = 1/5
2x -3(1/5) = 5
2x -3/5 = 5
2x = 5 +3/5 = 28/5
x = 14/5 = 2 4/5
2007-03-10 14:19:53 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
for the first equation the answer is y= + 4x-11
and the second equation the answer is y= 2/3 - 5/3
then u have to find where they intercept at
2007-03-10 14:13:38 · answer #4 · answered by confusedchick 3 · 0⤊ 1⤋
(-4x+y=-11 (3)
(2x-3y= 5
(-12x+3y=-33
(2x-3y= 5
-------------------
-10x = -28
x = 28/10 or 2,8
y = -11 + 4x
y = -11 + 4(2,8)
y = -11 + 11,2
y = 0.2
Solution: {(2,8; 0,2)}
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2007-03-10 14:22:41 · answer #5 · answered by aeiou 7 · 0⤊ 0⤋
2x-3(4x-11)=5
10x=28
x=2.8
y=0.2
2007-03-10 14:15:21 · answer #6 · answered by gummstein 1 · 0⤊ 0⤋
multiply bottom by 2
-4x+y=-11
4x-6y=10
----------------
-5y=-1
y=1/5
2x-3(1/5)=5
2x-3/5=5
2x=5.6
x=2.8
2007-03-10 14:14:08 · answer #7 · answered by leo 6 · 0⤊ 0⤋
sorry i cant answer that =(
2007-03-10 14:12:14 · answer #8 · answered by amandanl95 2 · 0⤊ 2⤋