"low oxidation state of vanadium with potassium tetraoxo manganate(vii)?

Answer 1

The "low oxidation state of vanadium" is V(I) or V+1
"Potassium tetraoxo manganate(vii)" is Potassium permanganate or KMnO4.

The reaction is dependant upon the actual conditions used (acidic or basic, etc.). In acid (like (HCl):

3 V+1 (aq) + 4 KMnO4 (aq) + 32 HCl (aq) --> 3 V+5 + 4 Mn+4 + 4 K+1 + 32 Cl- + 16 H2O (l)

Answer 2

uncertain what acac is, i assume that's a bidentate ligand that coordinates with the help of nitrogen atom lone pairs. if so, then vanadium looses 2 electrons to oxygen, so the oxidation state is V(2+)