For the function f(x) = 2x^2-5 find f(1) and f(-2)?

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2007-03-10 13:39:30 · 4 answers · asked by SadToday22 3 in Science & Mathematics ➔ Mathematics

f(x) = 2x^2-5
f(1) = 2(1)^2 - 5
f(1) = 2 - 5
f(1) = -3

f(x) = 2x^2-5
f(-2) = 2(-2)^2 - 5
f(-2) = 8 - 5
f(-2) = 3

f(1) = -3
f(-2) = 3

2007-03-10 13:45:50 · answer #1 · answered by dchosen1_007 2 · 0⤊ 0⤋

all ya gotta do is plug in the value to the function so f(1)=2*1^2-5
=2-5
=-3

and f(2)=2*2^2-5
=2*4-5
=8-5
=3

2007-03-10 21:46:18 · answer #2 · answered by MLBfreek35 5 · 0⤊ 0⤋

f(x) = 2xÂ²-5

f(1) = 2(1)Â²-5 = -3

f(-2) = 2(-2)Â²-5 = +3

2007-03-10 21:45:00 · answer #3 · answered by smci 7 · 0⤊ 0⤋

f(1)=-3
f(-2)=3

2007-03-10 21:52:31 · answer #4 · answered by JAMES 4 · 0⤊ 0⤋