Write the equation of the line w/ slope -2/3 and y-intercept of 4?

Answer 1

think of the general line equation:

y = mx + b

where :
y and x - represent coordinates
m - the slope
b - the y intercept

input given information

y = mx + b
y = -2/3x + 4

so, a general equation for any coordinate would be:

y = -2/3x + 4

Answer 2

undergo in concepts the equation for a line: y = mx + b m = slope b = y-intercept Given: slope = 2 / 3 replace your equation. y = mx + b y = (2 / 3)x + b Given: element (2, -5) skill: x = 2, y = -5 Plug those values into the equation you have and sparkling up for b. y = (2 / 3)x + b -5 = (2 / 3)(2) + b -5 = (4 / 3) + b -5 - (4 / 3) = b -5(3 / 3) - (4 / 3) = b (-15 / 3) - (4 / 3) = b (-19 / 3) = b replace your equation. y = (2 / 3)x + b y = (2 / 3)x + (-19 / 3) y = (2 / 3)x - (19 / 3) Subtract y from the two aspects. y - y = (2 / 3)x - (19 / 3) - y 0 = (2 / 3)x - y - (19 / 3) upload (19 / 3) to the two aspects. 0 + (19 / 3) = (2 / 3)x - y - (19 / 3) + (19 / 3) (19 / 3) = (2 / 3)x - y (2 / 3)x - y = (19 / 3) answer: (2 / 3)x - y = (19 / 3)

Answer 3

One equation for a line is Y = mX + b. m is the slope, and b is the y intercept. So the equation for this line would be Y = -(2/3)X + 4. Also, if you were given a slope (m) and a point (x1,y1), you can solve by using the equation ( Y - y1) = m ( X - x1), and after you plug it in, you can simplify it to the standard Y = mX +b form.

Answer 4

Well, just use the standard from y=m*x+b, where m is the slope and b is the y-intercept.

Answer 5

put it in y=mx+b form
m is the slope and b is the y-intercept
soo the anser is y= -2/3x+4

Answer 6

y = mx + b

they gave you slope and y-int, just plug them in

y = -2/3x + 4