Let Y=x (square) + 3, whats the domain and range
2007-03-10 13:18:09 · 5 answers · asked by jos3308 2 in Science & Mathematics ➔ Mathematics
Domain is the set of all possible x values. So, here the domain is the set of all real numbers, since you can square any number and add 3 to it. The range is the set of resulting y values. Here, y doesn't get any smaller than 3. So the range is {y| y >= 3}.
Graphs help alot.
2007-03-10 13:24:00 · answer #1 · answered by s_h_mc 4 · 0⤊ 0⤋
Okay the domain would be 1 since it's understood. The range would be 3
2007-03-10 21:38:32 · answer #2 · answered by Malcolm S 1 · 0⤊ 0⤋
y=x² + 3
when:
x = 0; y = 3 (0, 3)
x = 1; y = 4 (1, 4)
x = -1; y = 4 (-1, 4)
x = 2; y = 7 (2, 7)
Domain (f) = All Reais.
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2007-03-10 21:26:21 · answer #3 · answered by aeiou 7 · 0⤊ 0⤋
the domain is the input and the range is the output
2007-03-10 22:21:25 · answer #4 · answered by confusedchick 3 · 0⤊ 0⤋
y = x^2 + 3
domain: x can be any number
range: y >/ 3 because when you plug 0 for x, you get 3 and x^2 is positive so it opens up
2007-03-10 21:24:16 · answer #5 · answered by 7 · 0⤊ 0⤋