I have been trying to teach myself this stuff all day, and now my brain is MUSH!!! Looking for a math hero!!
(2 sqrt x- sqrt 4) (sqrt x + sqrt y)
2007-03-10 13:10:51 · 6 answers · asked by donnam4863 2 in Science & Mathematics ➔ Mathematics
(2sqrt(x) - sqrt(4))*(sqrt(x) + sqrt(y))
(2sqrt(x) - 2)*(sqrt(x)+sqrt(y))
2sqrt(x)*sqrt(x) +2sqrt(x)sqrt(y) -2sqrt(x) -2sqrt(y)
2*x +2sqrt(x)sqrt(y) -2sqrt(x) -2sqrt(y)
you can factor out a 2 and that's about it.
2007-03-10 13:16:30 · answer #1 · answered by Anonymous · 1⤊ 0⤋
2x+ 2 sqrt xy - 2 sqrt x + 2 sqrt y
2007-03-10 21:15:23 · answer #2 · answered by mgreens69 1 · 0⤊ 0⤋
You'll get four cross-products: 2x, -2 sqrt x, 2 sqrt (xy), -2 sqrt y. The result is the sum of all of these.
2007-03-10 21:22:10 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Use the FOIL method which is First, Outstide, Inside and Last. Multiply the First 2 terms then the Outside terms, the Inside terms and lastly, the Last terms. That is how you should get the answer.
2007-03-10 21:16:43 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I don't really understang your question.
Is it (2x^2 - 4^2)(x^2 + y^2) ?
If this your question, then
(2x^2 - 4^2)(x^2 + y^2)
2(x^2 - 2^2)(x^2 + y^2)
2[x^4 + (x^2)(y^2) - 4x^2 - 4y^2] (final answer)
*Hope this helps. I can only expand it, but can't solve it.
2007-03-10 21:27:55 · answer #5 · answered by dchosen1_007 2 · 0⤊ 0⤋
I have done pretty good in math and I think I can help you. Let me try!!!
Sorry, don't know!!! It looks like a bunch of nothing to me!!
2007-03-10 21:13:50 · answer #6 · answered by go clemson 2 · 0⤊ 4⤋