This is a question in my math class. Is the following set of numbers a perfect triple ? 7,15,18. Could someone please explain this to me ?
2007-03-10 12:32:02 · 5 answers · asked by wholelotta@sbcglobal.net 1 in Science & Mathematics ➔ Mathematics
As in, does it satisfy Pythagoras Theorem x² + y² = z² ?
Plugging them in:
7² + 15² ?= 18²
49 + 225 ?= 324
49 + 225 = 274 which is ≠ 324 so the answer is no.
2007-03-10 12:40:20 · answer #1 · answered by smci 7 · 1⤊ 1⤋
A perfect triple is basically an example of pythagoras in which all three sides of a right angled triangle are integers.
So the longer side squared is equal to the sum of the squares of the other two sides.
If 7, 15, 18 is a triple, 7² + 15² = 18²
7² = 49
15² = 225
18² = 324
49 + 225 â 324
So 7, 15, 18 is not a perfect triple.
2007-03-10 20:41:26 · answer #2 · answered by Tom :: Athier than Thou 6 · 0⤊ 0⤋
no. a perfect triple has the sum of the squares of the first two terms equal to the square of the largest term.
but for these three numbers:
18^2=324
7^2+15^2= 274
since 324 does not equal 274, this is not a perfect triple.
2007-03-10 20:40:49 · answer #3 · answered by jaybee 4 · 1⤊ 0⤋
If you are asking about Pythagorean triples, then no.
7^2 + 15^2 does not = 18^2
2007-03-10 20:41:15 · answer #4 · answered by Jerry P 6 · 0⤊ 0⤋
to find out if it is a pythagorean triple, you use the formula a^2 + b^2 = c^2
since c is the hypotenuse, it has to be the longest side. a, b are two sides.
so, 7^2 + 15^2 = 18^2
274 does not equal to 324
therefore, 7, 15, and 18 is not a perfect triple.
2007-03-10 20:41:17 · answer #5 · answered by Anonymous · 0⤊ 0⤋