divide 12/3 = 4
x^7/x^4=x^3 (you subtract the exponents)
y^6/y^3=y^3
so answer
4x^3y^3
2007-03-10 12:30:14
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answer #1
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answered by leo 6
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Okay. You have 12x^7y^6/ 3x^4y^3. When you are dividing variable numbers with exponents, start with one variable, like x here. You have 12x^7 on top and 3x^4 on the bottom. You can do two things to these. 12 is divisible by 3, and they both have common variables so you divide that and get 4. Then since they are both exponents of x, and you are dividing, you subtract the exponents of x. So you have x^7-x^3= x^3. So the first part of the answer is (4x^3). Then you do the same with the next variable. You have y^6/ y^3. You don't have any variables, or it's understood to be 1. You can just subtract the exponents here to get y^3. Put it all together and you have 4x^3y^3. Remember that when you multiply exponents you add, dividing you subtract.
2007-03-10 20:41:33
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answer #2
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answered by Leigh K 3
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Divide numbers, subtract exponents
4x^7-4y^6-3 = 4x^3y^3
2007-03-10 20:30:34
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answer #3
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answered by richardwptljc 6
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Step 1: Divide the coefficients (The numbers at the front)
12/3=4
Step 2: x^7/x^4 = x^(7-4) = x^3
Step 3: y^6/y^3 = y^(6-3) = y^3
Answer: 4x^3y^3
2007-03-10 20:31:33
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answer #4
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answered by gumtrees 3
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(12x^7y^6)/(3x^4y^3)=
look at the like variables and collect the terms:
(12/3)(x^7/x^4)(y^6/y^3)=
4x^3y^3
2007-03-10 20:32:24
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answer #5
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answered by jaybee 4
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(12x^7y^6 )/(3x^4y^3) = 12/4 *( x^7/x^4)*(y^6/y^3) = 3*x^(7 -3) * (y^(6 - 3) = 3*(x^3)*(y^3)
2007-03-10 20:34:35
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answer #6
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answered by physicist 4
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first, split the eqn into two parts:
Part 1:12(x^7)/3(x^4)
Part 2: (y^6)/(y^3)
For part 1, 12/3=4, (x^7)/(x^4)=(x^3)
For part 2, (y^6)/(y^3)=(y^3)
Combine, answer is 4(x^3)(y^3)...
2007-03-10 20:35:49
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answer #7
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answered by gummstein 1
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12x^7y^6/(3x^4y^3=4x^2y^3
2007-03-10 20:32:18
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answer #8
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answered by yupchagee 7
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4x^3 y^3
2007-03-10 20:30:46
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answer #9
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answered by Anonymous
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