What is [ OH - ] for a solution where pH = 8.40?

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2007-03-10 10:36:50 · 2 answers · asked by Russell M 1 in Science & Mathematics ➔ Chemistry

okay guys i did this k....

10^-5.6 = .000003

but its still wrong help please!!!!

2007-03-10 12:42:39 · update #1

Subtract 8.4 from 14.0 to get 5.6.

Then [OH-] = 10 to the power of -5.6.

2007-03-10 10:45:45 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋

pH + pOH = 14
pOH = 14 - 8.40
[OH]= antilog (-5.6)

use calculator

2007-03-10 18:47:05 · answer #2 · answered by Anonymous · 0⤊ 0⤋