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That was worded terribly, but wut i'm tryin to say is....
let's say someone's 90 lbs... in order to keep their feet on the ground, does the earth's gravity pull them down with a force equal to their weight? is there a way to specifically define this amount of force in a way other than the acceleration of an object towards the earth (9.8 m/s2)???

2007-03-10 10:14:52 · 4 answers · asked by smilepalooza12 1 in Science & Mathematics Physics

4 answers

The force of gravity IS the weight of the object.
Gravity exerts a force on the object; this force is the object’s weight.

If an object has a mass of, for example, 10 kg, and the gravitational acceleration due to the Earth is 9.8 m/s^2, the weight of the object is 98 Newtons.

Where m and M are the masses of the object and the Earth.
To get the gravitational acceleration of an object (like the Earth) with mass M,
a = G * M / r^2
Using Newton’s 2nd law, F = ma,
Force of gravity = m * a, where a is described above.
From this we can get,
Newton’s law of universal gravitation,
F = G * m * M / r^2

2007-03-10 10:21:08 · answer #1 · answered by mrjeffy321 7 · 0 0

The weight is just the force which the earth applies on a person due to gravity

2007-03-10 10:19:39 · answer #2 · answered by santmann2002 7 · 1 0

well force = mass x acceleration

accelleration due to gravity on earth = g (constant)

Force due to gravity = g * m

so the force is g*m.

Isnt that kinda obvious?

2007-03-10 10:39:53 · answer #3 · answered by thereytrain 2 · 0 1

Yes! gravity is what gives (causes) all matter the property we all call "weight"

2007-03-10 10:29:59 · answer #4 · answered by occluderx 4 · 0 1

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