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A lawn mower can cut the park lawn in 10 hours. A different mower can cut the same lawn in 12 hours, and a third type can cut it in 15 hours.

How do you solve this?
:/

Thank you

2007-03-10 05:28:25 · 3 answers · asked by Victoria 1 in Education & Reference Homework Help

3 answers

Mower one: 1/10 of park in one hour.
Mower two: 1/12 of park in one hour.
Mower three: 1/15 of park in one hour.

Total in one hour with all three mowers:

1/10 + 1/12 + 1/15 = total Change to 60ths
6/60 + 5/60 + 4/60 = 15/60 = 1/4 of the park in an hour

2007-03-10 05:41:28 · answer #1 · answered by ecolink 7 · 0 0

(x/10 + x/12 + x/15 = 1) x 60
6x + 5x + 4x = 60
15x = 60
x = 4 hours --> time it takes to mow the whole lawn
therefore, 1/4 of the mowing could be done in 1 hour.

2007-03-10 13:42:17 · answer #2 · answered by Newbody 4 · 0 0

answer is 1/4.
1/10+1/12+1/15=15/60 (work done by all three in 1 hour)

2007-03-10 13:43:23 · answer #3 · answered by skepty 3 · 0 0

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