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please show step by step

2007-03-10 05:23:50 · 10 answers · asked by Josh Muller 1 in Science & Mathematics Mathematics

10 answers

x^2-4X-12 = 0 you subtract 12 from both sides

remember, you need to find two numbers that multiply to 12 and add to -4....and one of them has to be negative.

lets write out factoring pairs of 12...1,12 2, 6 3,4
-6 and 2 work

(x-6) (x+2) = 0

to solve for x:::

you need to realize that either "x-6" or "x+2" is equal to zero (or both), if their product is zero (zero product theorum)

so we set them equal to zero

x-6=0
x+2=0

there are two answers, 6 and -2

this is commonly expressed as x = {-2; 6}

2007-03-10 05:30:40 · answer #1 · answered by Spearfish 5 · 0 0

First, subtract the twelve and set the equation equal to 0: x^2-4x-12=0
Next, find all the factors of -12 : (1,-12) (-1,12) (-2, 6) (2,-6) (3, -4) (-3, 4)
Then pick the two that add up to -4: (2, -6)
Then factor it out: (x-6)(x+2)=0
Set the answers equal to 0: (x-6=0) (x+2=0)
Solve for x: (x=6) (x=-2)

Hope that helps!

~queenpan1295

2007-03-10 05:30:54 · answer #2 · answered by queenpan1295 3 · 0 0

In order to factor this equation, all values need to be on the same side. Like this:
X squared - 4X = 12 Subtract 12 from both sides.
X squared - 4X - 12 = 0 Factoring the equation
(X - 6)(X + 2) = 0

2007-03-10 05:35:33 · answer #3 · answered by SlownEasy 4 · 0 0

x^2 - 4x = 12
x^2 - 4x - 12 = 12 - 12
x^2 - 4x - 12 = 0
(x - 6)(x + 2) = 0

Therefore: the factors are: (x - 6) and (x + 2).

2007-03-10 05:27:44 · answer #4 · answered by Steven 4 · 0 0

x^2 -4x =12

x^2 -4x -12 =0

By splitting the middle term,

x^2 -6x +2x -12 =0 ( -6+2=-4 and -6 x 2 = -12)

x(x-6) +2(x-6) =0

(x+2) (x-6) = 0

x+2=0 or x-6=0

x= -2 or x =6

2007-03-10 17:15:32 · answer #5 · answered by ash 2 · 0 0

subtract 12 for both sides

x^2 - 4x - 12 = 0

look for two numbers that multiply to -12 and add up to -4.

-6 and 2

(x-6)(x+2)

hope this helps

2007-03-10 05:29:44 · answer #6 · answered by      7 · 0 0

given eqution x^2 -4x=12
x^2 -4x -12=0
here numbers whose addition is -4 and multiplication is -12
are -6 and 2
therefore
x^2 -6x +2x -12=0
x(x-6)+2(x-6)=0
(x-2)(x-6)=0

so x-2 =0 and x-6=0 are two factor of it.

2007-03-10 05:31:08 · answer #7 · answered by Anonymous · 0 0

x² - 4x = 12

x² - 4x + ______ = 12 + _____

x² - 4x + 16/4 = 12 + 16/4

(x - 4/2)(x - 4/2) = 48/4 + 16/4

(x - 4/2)² = 64/4

(√x - 4/2)² = ± √64 / √4

x - 4/2 = ± 8 / 2

x - 4/2 + 4/2 = 4/2 ± 8/2

x = 4/2 ± 8/2

- - - - - - - - - - - -

solving for +

x = 4/2 + 8/2

x = 12 /2

x = 6

- - - - - - -

Solving for -

x = 4/2 - 8/2

x = - 4 / 2

x = - 2

- - - - - - - -s-

2007-03-10 08:18:43 · answer #8 · answered by SAMUEL D 7 · 0 0

You need to specify the number field you are working in. Also are you factoring into elements or ideals? (e.g. you may not even have unique factorization).

2007-03-10 11:29:31 · answer #9 · answered by Dulcy L 1 · 0 0

x*x - x*x*x*x = 12
-x*x=12
-(-6*-6)=12
x= -6 i think

2007-03-10 05:31:31 · answer #10 · answered by answernaut 2 · 0 0

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