2007-03-10 05:20:38 · 5 answers · asked by goring 6 in Science & Mathematics ➔ Astronomy & Space
Physics-wise, "escape" implies zeroing out the potential energy, so the "escape" velocity of 7 mi/s requires travelling infinitely far away, which, obviously, would take infinite time.
However, on a more practical level, let's say that point is where the gravitation attraction drops to 0.1% of the surface value. Then, you can calculate the time required to travel that distance at 7 mi/s. So,
1000re/7mi/s ~ 157 hrs
2007-03-10 05:33:32 · answer #1 · answered by arbiter007 6 · 0⤊ 0⤋
it is via the escape velocity of the Earth that's 11.2 km/sec. escape velocity is defined because of the fact the minimum velocity with which a physique could be projected such that it escapes from the earth's gravitational pull completely (Air resistance is omitted). whilst the inspiration advise sq. of a physique is extra effective than the escape velocity of the earth it escapes from the earth neglecting its mass. it is the theory utilized to the rockets.
2016-11-23 19:23:48 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Obviously other variables are invovled (thrust, mass etc) you need to know those before you can get the answer.
2007-03-10 05:25:42 · answer #3 · answered by LeChugh 2 · 0⤊ 0⤋
Depends upon how fast it is going and how far away it can get.
2007-03-10 05:24:21 · answer #4 · answered by occluderx 4 · 0⤊ 0⤋
about seven miles per second.
2007-03-10 05:25:48 · answer #5 · answered by breeze1 4 · 1⤊ 0⤋