y = e ^ -5x times cos 3x?

0 ⤊

y = e ^ -5x times cos 3x?

Using the chain rule. please show steps. thanks!!

2007-03-10 03:56:38 · 3 answers · asked by soccerdogg6 2 in Science & Mathematics ➔ Mathematics

3 answers

1. take the deriv of e^-5x, multiply by cos 3x
-5e^-5x (cos 3x)
2. take the deriv of cos 3x, multiply by e^-5x
-3(sin3x) *e^-5x
3. put them together
-5e^-5x(cos 3x) -3(sin3x)e^-5x

2007-03-10 04:15:38 · answer #1 · answered by mstnglover 2 · 0⤊ 0⤋

This site will show you the working and solve derivatives for free
http://www.calc101.com/

2007-03-10 04:34:30 · answer #2 · answered by rg 3 · 0⤊ 0⤋

y'= e^-5x(-5)(cos3x)-e^-5x(sin3x)*3=

-(e^-5x)(5cos3x +3sin3x)

2007-03-10 09:08:07 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋