4 / a^2-1 + 1 / 2a+2
(4 over 'a' squared - 1, plus 1 over 2a+2)
I cannot find my LCD. Can someone show me how to do this to solve. Thank you. :)
2007-03-10 03:08:18 · 5 answers · asked by h4a3p2p1y 1 in Education & Reference ➔ Homework Help
That's 4/(a^2 -1) + 1/(2a+2)
The first term is 4/[(a+1)*(a-1)]
The second term is 1/[2(a+1)]
Both have the term (a+1) in the denominator.
So you can rewrite as 1/(a+1) * [4/(a-1) + 1/2]
2007-03-10 03:14:40 · answer #1 · answered by Anonymous · 1⤊ 1⤋
That's 4/(a^2 -1) + 1/(2a+2)
The first term is 4/[(a+1)*(a-1)]
The second term is 1/[2(a+1)]
Both have the term (a+1) in the denominator.
So you can rewrite as 1/(a+1) * [4/(a-1) + 1/2]
Hope that helped! I'm a genius with an iq of 249
2007-03-10 12:00:17 · answer #2 · answered by Anonymous · 0⤊ 0⤋
I multiplied both sides by one-fourth (1/4) and simplified everything to 1/16a + 1/a^2
I might have done it wrong but I hope that helps!
2007-03-10 11:14:47 · answer #3 · answered by Anonymous · 0⤊ 2⤋
First... you have to use.. square the 'a' than combine like terms.
2007-03-10 11:12:20 · answer #4 · answered by ♦Its•Possible•But•Not•Logical♦ 3 · 0⤊ 2⤋
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2007-03-10 11:11:01 · answer #5 · answered by Ghost 2 · 0⤊ 2⤋