Hydrochloric acid is widely used as a laboratory reagent, in refining ore for the production of tin and tantalum, and as a catalyst in organic reactions. Calculate the moles of solute in 62.85 mL of 0.453 M hydrochloric acid. (M = 36.46 g/mol)
a. 0.0285 mol
b. 0.00721 mol
c. 0.139 mol
d. 1.04 mol
2007-03-10 02:24:57 · 3 answers · asked by godrics 2 in Science & Mathematics ➔ Chemistry
a liter of 0.453 M HCl has 0.453*36.46 =16.51g/Liter
and 62.85 ml has 0.06285*16.51 =1.04g/l
containing 1.04/36.46 = 0.0285 mole/L
2007-03-10 02:33:25 · answer #1 · answered by maussy 7 · 0⤊ 0⤋
molarity is moles in a liter of solution. 1 M means one mole in one liter.
You have 0.453M in 62.85 ml (0.0625 liters)
0.453 M would be (0.453mol)(36.46 g/mol) grams in 1 liter. Now set up a ratio to see how many grams in 0.0625 liters
2007-03-10 10:37:33 · answer #2 · answered by reb1240 7 · 0⤊ 0⤋
Molarity is moles/Liters of solution. If you multiply sides by Liters, you get the # of moles = Liters of solution * the Molarity. If you multiply these together in your probelm, you gat 0.0285 mol, or a.
2007-03-10 10:34:00 · answer #3 · answered by dios_et_dios 2 · 0⤊ 0⤋