x^3 z^4 / x z^5
2007-03-10 02:10:39 · 9 answers · asked by Help please 1 in Science & Mathematics ➔ Mathematics
= x^(3-1) * z^(4-5)
= x^2 * z^(-1)
=x^2/z
2007-03-10 02:15:38 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The answer is x^2 / z.
When dealing with powers, just remember that when you have two terms multiplied together, i.e. (x^3)(x^5) you just add the powers, giving x^8. This also works with dividing, you just subtract the powers.
So in your example x^3 z^4/ x z^5, for the x term, you have 3-1, which = 2, and for the z term you have 4-5, which = -1, which gives x^2 z^-1, which is = to x^2 / z.
Hope this helps!
2007-03-10 10:19:49 · answer #2 · answered by drummanmatthew 2 · 0⤊ 0⤋
since they are all being multiplied together we can rewrite this as:
(x^3/x)*(z^4/z^5)
x^3=x*x*x
so x^3/x = x*x = x^2
whenever we divide by a power of the same base we subtract the power.
applying this to the second part
z^4/z^5 = z^(4-5) = z^-1 or 1/z
so x^3 z^4 / x z^5 = x^2 / z
2007-03-10 10:17:03 · answer #3 · answered by emily 2 · 0⤊ 0⤋
remember x^b *x^c = x^(b+c) x^b /x^c = x^(b-c)
so x^3 z^4 /x z^5 = x^(3-1) z^(4-5) = x^2 z^(-1) = x^2/z
2007-03-10 10:19:12 · answer #4 · answered by maussy 7 · 0⤊ 0⤋
x^2/z
2007-03-10 10:19:57 · answer #5 · answered by rwbblb46 4 · 0⤊ 0⤋
x^3-1= x^2
z^4-5= z^-1
Answer= x^2/z
2007-03-10 11:02:13 · answer #6 · answered by spazgrl100 1 · 0⤊ 0⤋
x^2
----
z
2007-03-10 10:41:37 · answer #7 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
x^3z^4/xz^5
=x^2/z
2007-03-10 10:27:16 · answer #8 · answered by alpha 7 · 0⤊ 0⤋
x^3z^4/xz^5=
x^2/z
2007-03-10 10:18:39 · answer #9 · answered by bignose68 4 · 0⤊ 0⤋