solve this?

Question

solve u^4 = 1 where u is a real number.
simplify the answer as much as possible

If there is more than one solution than write them all.

Answer 1

u^4=1
so you need the 4th root of 1
u= +1 or -1

Answer 2

This is so simple the roots are 1 and -1

Remember negative and positive numbers if raised with an even power will give the same result. In this case, -1 and 1 are raised with 4 (even number) always produce postive 1. However an odd power number is a differrent story

Answer 3

I suppose you want to solve it in complex numbers
u= 1^1/4 = 1< 2kpi/4 = 1 k=0 u=1<0=1
k=1 u= 1 k=2 u=1 k=3 u=1<3pi/2 =-i

Answer 4

I think the answer is 1 and -1.

Answer 5

u^4 = 1

so, u^2 = +1 or -1

for u^2 = +1, u = +1 or -1

for u^2 = -1, u = sqrt -1 = +j or -j where j = sqrt -1

So, +1, -1, +j and - j are the possible roots

Answer 6

u = 1, or -1 because both of them to the fourth power is 1

Answer 7

the answer is 1

Answer 8

I think 1/4 or .25

Answer 9

only two values -1 and +1