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a) 4x2^5 / 8
b) a^2 b^3/a^3 b^2

???

2007-03-10 01:46:27 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

a) 4x²^5 / 8 =
2²x¹º / 2³ = x¹º over 2
b) a² b³/a³b² = b over a
:==::

2007-03-10 02:05:41 · answer #1 · answered by aeiou 7 · 0 0

a) You need to make everything into powers of 2.

4=2^2
8=2^3

this gives:

(2^2 * 2^5)/2^3
When you have the same base(in this case 2) being multiplied, we add the indicies, so:
2^2 * 2^5 = 2^7

When dividing by a power with the same base we subtract, so:
2^7/2^3=2^4

b)since it is all being multipied together we can rewrite
(a^2 b^3)/(a^3 b^2) as (a^2/a^3)*(b^3/b^2)

using what we learnt in the first question:
a^2/a^3=a^-1 or 1/a^1

b^3/b^2=b^1 or b

so the solution is b/a

2007-03-10 10:10:31 · answer #2 · answered by emily 2 · 0 0

a) 4*4=16

b) b/a

2007-03-10 09:58:56 · answer #3 · answered by iyiogrenci 6 · 0 0

your kidding right??? you dont know this...

2007-03-10 09:51:00 · answer #4 · answered by Anonymous · 0 0

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