my mom was 27 when i was born. 8 yrs ago she was twice as old as i shall be in 5 yrs tme. how old am i now?
2007-03-10 01:43:04 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
you are age x
in 5 years time you will be x + 5
your mother is 27+x assuming she ages the same way we all do and is not a Time Lord from Gallifrey
8 years ago, she was twice what you will be in 5 years time
27+x-8 = 2(x+5)
19+x = 2x + 10
Solve for x, you happy 9 year old
No wonder you can't do algebra
2007-03-10 01:47:23 · answer #1 · answered by Orinoco 7 · 0⤊ 0⤋
You would be 4 years old because when you were born your mother was 27 supposing that your mother is 48 because it has to be a number that if you subtract 8 it gives 0 or 5 as a ones place. Now, you need to know how old are you relating the age of your mother, you have the information that your mother is 48(example) you subtract 8 and it is 40, it functions because the number´s one place is 0 so, the age that we actually have is 40and you say it is twice as old so 40 divided 2 is 20 and the age you will be in 5 years so, 20 divided 5 is 4 so, you are 4 years old.
2007-03-10 07:09:00 · answer #2 · answered by Helpy 1 · 0⤊ 0⤋
Let your present age be x
Turn your problem into a linear equation in one variable.
The required Equatins is:
27 + x- 8 = 2(x + 5)
19 + x = 2x + 10
x + 10 = 19
x = 9
2007-03-10 02:11:29 · answer #3 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
your age is x
after 5 yrs, x+5(add)
then ur mom'll be 27+x
she was two times 8yrs ago what you will be in 5 years time
then,
27+x-8 = 2(x+5)
solve,
19+x = 2x + 10
19-10=2x-x
9=x and that's ur age.
ur question is really nice
2007-03-10 01:56:27 · answer #4 · answered by pprr 2 · 0⤊ 0⤋
x = present age
27 + x = moms present age
27+x -8 =2(5+x)
19 + x = 10 +2x
9 = x
2007-03-10 02:05:36 · answer #5 · answered by bignose68 4 · 0⤊ 0⤋
your not born yet?
2007-03-10 01:45:57 · answer #6 · answered by Anonymous · 0⤊ 0⤋