where w is a real number
(sqrt 8w - 14) = (sqrt 5w + 8)
if there is more than one solution write them all
2007-03-10 01:41:27 · 5 answers · asked by Tracey N 1 in Science & Mathematics ➔ Mathematics
square both sides
8w - 14 = 5w + 8
subtract 5w from both sides
add 14 to both sides
divide both sides by 3
you'll get your solution
Hmmm
Bhajun makes a good point
Do you mean (sqrt (8w-14)) = (sqrt (5w+8))
or do you mean (sqrt(8w) - 14) = (sqrt(5w) + 8)?
cos if you do, that's a little different
2007-03-10 01:45:24 · answer #1 · answered by Orinoco 7 · 1⤊ 0⤋
(sqrt 8w - 14) = (sqrt 5w + 8)
Square both sides:
8w - 14 = 5w + 8
3w = 22
w = 22/3
2007-03-10 10:15:06 · answer #2 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
â8w-14=â5w+8
Square both sides:
8w-14=5w+8
Subtract 5w from both sides:
3w-14=8
Add 14 from both sides:
3w=22
Divide 3 from both sides:
w=22/3
Check:
â8(22/3)-14=â5(22/3)+8
â176/3-42/3=â110/3+24/3
â134/3=â134/3
I hope this helps!
2007-03-10 09:51:47 · answer #3 · answered by Anonymous · 0⤊ 0⤋
sqrt(8w) - 14 = sqrt(5w) + 8
sqrt(8w) - sqrt(5w) = 22
[sqrt(8) * sqrt(w)] - [sqrt(5) * sqrt(w)]
sqrt(w) * [sqrt(8) - sqrt(5)]
sqrt(w) = 22 / [sqrt(8) - sqrt(5)]
w = 1379.35
2007-03-10 09:47:58 · answer #4 · answered by Bhajun Singh 4 · 0⤊ 0⤋
sqrt8w -sqrt5w = 22 (wmust be >=0(
squaring ( later you must verify)
13w-2sqrt40w^2 =484
(13-4sqrt10)w = 484
w=484/(13-4sqr10) = 484(13+sqrt10)/9
2007-03-10 09:57:27 · answer #5 · answered by santmann2002 7 · 0⤊ 0⤋