round answer to the nearest tenth
sides are x, 20 & 11
I came up with 16.70 is this right????
2007-03-10 01:38:46 · 7 answers · asked by Tracey N 1 in Science & Mathematics ➔ Mathematics
According to Pythagoras theorem,
x^2 + 11^2 = 20^2
x^2 + 121 = 400
x^2 = 279
x = sqrt (279)
x = 16.703293088490065766358413896756
x = 16.70 (approximate)
Yep, you're right.
2007-03-10 02:17:35 · answer #1 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
so what's the question? in case you pick to look for the dimensions of the two aspects of the triangle then with the given length of x inches, x + a million inches and x + 2 inches and a edge of 40 two inches, The length of area x is : Perimeter = x + (x + a million)inches + ( x +2) inches = 40 two inches x + x + a million + x +2 = 40 two inches 3x + 3 inches = 40 two inches 3x = 40 two - 3 inches 3x = 39 inches x = 13 inches; which length of one sideTo sparkling up for the different 2 aspects: x + a million = 13 + a million = 14 inches x + 2 = 13 + 2 = 15 inches Now, we've the dimensions of the three aspects of the triangle that are 13, 14, and 15 inches.
2016-11-23 19:06:32 · answer #2 · answered by Anonymous · 0⤊ 0⤋
No a triangles 2 shortest sides must must be greater then the length of the longest side. The longest side must be 20 and 2x11 is 22. The asnswer is 11.
2007-03-10 01:47:35 · answer #3 · answered by craftyboy 2 · 0⤊ 0⤋
sq. rt (sqr 20-sqr 11) = x
sq.rt(400-121) =x
sq.rt(279)=x
the answer is 16.7(approximately)
so ur answer 16.70 is right
u r a genius
2007-03-10 02:05:40 · answer #4 · answered by pprr 2 · 0⤊ 0⤋
Sounds about right. (I got the sqrt of 279, but don't have a calculator handy to finish the problem.)
2007-03-10 01:45:42 · answer #5 · answered by Anonymous · 0⤊ 0⤋
400= 121+x^2 (Pythagoras) x= sqrt279=16.7
2007-03-10 02:04:29 · answer #6 · answered by santmann2002 7 · 0⤊ 0⤋
Should be correct. That's what I came up with also.
2007-03-10 01:47:16 · answer #7 · answered by Anonymous · 0⤊ 0⤋