As mentioned, it can only be either an alkene or a cycloalkane, since you only have one unsaturation.
Structurally, you can have any of the following:
1-butene
2-butene
2-methylpropene
cyclobutane
methylcyclopropane
Of those, only 2-butene will have stereoisomers, cis (two CH3 groups on same side of molecule) and trans (opposite sides).
2007-03-10 00:53:53
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answer #1
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answered by TheOnlyBeldin 7
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Lets see -
C4H8 - automatically an alkene or cycloalkane
alkenes -
cis- and trans- configurations (also referred to as E and Z) are stereoisomers.
there is no chiral center hence no enantiomers
location of the double bond - diastereomers ( 1-butene, 2-butene)
methyl cyclopropane - location of methyl group with relation to the double bond (1-methyl cyclopropane, 2-methyl cylcopropane)
could also have a cylcopropane with a double bond in the side group however unlikely.
cyclobutane -all conformations are equivalent
Hope that starts you off
2007-03-10 00:14:54
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answer #2
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answered by Ravindra G 2
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1... But-1-ene ... CH2=CH-CH2-CH3 ... C4H8
2... But-2-ene ... CH3-CH=CH-CH3 ... C4H8
3... 2-Methylpropene ... CH2=C(CH3)-CH3 ... C4H8... (The methyl group forms a branch off the middle Carbon).
4... Methyl cyclo-propane ... 3 carbons in a ring with 1 attached to a methyl group. (Saturated). C4H8.
The following is not an isomer but is C4H8.
5...Cyclo-butane ...Carbons form a ring .. saturated...C4H8
2007-03-10 08:43:42
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answer #3
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answered by Norrie 7
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There are 4 isomers and two stereo isomers of each other
These include but-1-ene, but-2-ene (including the two stereo isomers cis-but-2-ene and trans-but-2-ene), 2-methyl-propene and cyclobutane (the only cycloalkane).
Hope that helps. There structures can be found in this website http://www.slc.ac.nz/WorkshopClub/Workshop/answersproblemsgeometricisomers.htm
2007-03-10 00:36:54
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answer #4
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answered by The exclamation mark 6
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Three types
But-1-ene and but-2-ene
but-1-ene does NOT have cis/trans isomerism.
but-2-ene does have cis/trans isomerism.
2007-03-10 08:39:11
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answer #5
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answered by lenpol7 7
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Six different isomers can be formed by the above formula
1.butene-1
2.cis-2 butene
3.trans-2-butene
4.2-methylpropene
5.cyclobutane
6.methylcyclopropane
2007-03-10 01:04:02
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answer #6
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answered by dushyant 1
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CH2=CH-CH2-CH3
CH3-CH=CH-CH3
CH3-C=CH2
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CH3 (This one should be on the second C)
2007-03-10 00:17:41
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answer #7
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answered by tuoidabuon 2
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