1. Two mating fruit flies each have one gene for black eyes and one for red eyes. The offspring receive one ey

Question

1. Two mating fruit flies each have one gene for black eyes and one for red eyes. The offspring receive one eye-colour gene from the male and one from the female.

a) Produce a tree diagram showing all the possible combinations for the offspring.

b) How many distinct combinations can be produced?

Answer 1

i think a gene i.e either red or black will have the same effect irrespective of whether it is derived from the male or female

1.TREE DIAGRAM(depending on from who it is derived v will have 4 trees)

(a) (m)+(f)=(mb,fb)
(b) (m)+(f)=(mb,fr)
(c) (m)+(f)=(mr,fb)
(d) (m)+(f)=(mr,fr)

2. DISTINCT COMBINATIONS

it can only b 3
(b,b) (r,r) (b,r)

[here (b,r) is same as (r,b) from assumption]

Answer 2

First you are able to look on the ratios modern-day. note that the ruby adult males and red adult males are chop up about 50-50 and the ladies and adult males are chop up 50-50. a) ruby eyes are recessive because not one of the ladies have them. b) The ruby eye colour is sex appropriate because they don't look modern-day in females and are modern-day in 1/2 the adult males. c) the male could be x^R Y so each and each of the ladies are dominant (sex is determined by technique of the adult males because the female must have an x from the daddy) and the female could be x^R x^r so as that the adult males have a 50-50 threat of having both. d) the female baby are chop up 1/2 and 1/2 between the following genotypes because they have a 50-50 threat of inheriting both of the x's from the mother: x^r x^r x^R x^r e) red eyed adult males are x^R Y ruby eyed adult males are x^r Y because they ought to have a y chromosome. wish this enables :)

Answer 3

Female Fruit Fly --- black_f
--- red_f
Male fruit fly ---- black_m
---- red_m
So the baby could get

black_f/red_m
black_f/black_m
black_m/red_f
red_m/black_f
red_f/red_m


You'll have to do the tree digram yourself