Dewd....... You *really* need to read your text book. Just add the coefficients of like powers of x and you get
-(1/2)x^4 + (7/9)x^3 +x^2
Now get your butt in gear and *learn* this stuff. Preferably *before* your next math test ☺
Doug
2007-03-08 23:31:07
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answer #1
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answered by doug_donaghue 7
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When we add or substract polymonials with same degree , actually the cooefficient are added or substracted.Therefore,
(1/4 -3/4) x^4 + 7/9 x^3+ ( 3/8 + 5/8) x^2 + (4-4)
or -1/2 x^4 + 7/9 x^3 + x^2 , That's the Answer
2007-03-09 00:23:04
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answer #2
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answered by ritesh s 2
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1) When adding polynomials you simply collect terms with the same exponent.
2) Given
U(x) = X^4/4 +7x^3/9 + ...
3) Apply the rule in 1)
U(x) = x^4[1/4-3/4] + x^3[7/9] + x^2[3/8+5/8] + x^1[0] + x^0 [4-4]
4) Simplifying
U(x) = x^2 ( -x^2/2 + 7x/9 +1 )
5) Finally
U(x) = -x^2( 9x^2 - 14x -18 ) / 18
2007-03-08 23:54:06
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answer #3
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answered by 1988_Escort 3
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1/4x^4 + 7/9x³ + 3/8x² + 4
-3/4x^4 + 0x³ + 5/8x² - 4
----------------------------------
-2/4x^4 + 7/9x³ + 8/8x² + 0 = x²(-1/2x² + 7/9x + 1)
Answer: x²(-1/2x² + 7/9x + 1)
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2007-03-08 23:40:35
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answer #4
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answered by aeiou 7
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-1/2x^4 +7/9x^3 +1/x^2
2007-03-08 23:27:53
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answer #5
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answered by Amit Y 5
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-1/2x^4 + 7/9x^3 + x^2
2007-03-08 23:26:46
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answer #6
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answered by Leigh K 3
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(1/4x^4 + 7/9x^3 + 3/8x^2 + 4) + (-3/4x^4 + 5/8x^2 - 4) =
1/4x^4 + (-3/4x^4) + 7/9x^3 + 3/8x^2 + 5/8x^2 + 4-4 =
1/4x^4 - 3/4x^4) + 7/9x^3 + 3/8x^2 + 5/8x^2 + 4-4 =
-1/2x^4 + 7/9x^3 + 8/8x^2 + 0 =
-1/2x^4 + 7/9x^3 + x^2
2007-03-08 23:25:35
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answer #7
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answered by Ms. S 5
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It's not as hard as it looks,...
(1/4) x^4 + (7/9)x^3 + (3/8)x^2 + 4
(-3/4)x^4 +................ (5/8)x^2 - 4
----------------------------------------------------
(-2/4)x^4 + (7/9)x^3 + (8/8)x^2
Reduce fractions:
(-1/2)x^4 + (7/9)x^3 +x^2
Subtract the equations in a column keeping LIKE terms "lined up",.. x^4,.x^3, etc.
Then subtract coefficients.
2007-03-08 23:32:48
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answer #8
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answered by RockHanger 3
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-1/2x^4 + 7/9 x^3 +x^2 = x(-1/2x^2 + 7/9 x^2 +x)
2007-03-08 23:25:46
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answer #9
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answered by John S 6
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2016-10-17 22:51:43
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answer #10
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answered by Anonymous
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