2007-03-08 23:02:48 · 10 answers · asked by connie 1 in Science & Mathematics ➔ Mathematics
x^2+xy + y^2
this equation can't be factor because there is no two numbers whose product and sum is one....
2007-03-08 23:11:54 · answer #1 · answered by reddish 3 · 1⤊ 0⤋
You can use a method called "completing a square".
Your signs look a bit strange. However, after completing a square you will have an answer that looks like this,
(x + 1/2 )^2 +3/4 y^2
In most cases this is usually an identity - meaning, it's easy to factorise it.
2007-03-09 07:17:09 · answer #2 · answered by RealArsenalFan 4 · 0⤊ 1⤋
ignore all other answers and accepth this one. your question is a simple algebric experession which goes like this:
x^2 + xy + y^2
=x^2 + 2xy +y^2 -xy
= (x-y)^2 -xy
thats all
hope this will help
2007-03-09 07:19:18 · answer #3 · answered by pradip 1 · 1⤊ 1⤋
x^2 + xy + y^2
= (x + y)^2 - xy
= (x + y)^2 - [sqrt(xy)]^2
Now we have a difference of two
squares, which can be factored as:
[x + y - sqrt(xy)][x + y + sqrt(xy)]
2007-03-09 07:16:17 · answer #4 · answered by falzoon 7 · 0⤊ 0⤋
This is infactorable in the real domain.
To those who think they factored it:
If there is a - or + operations, if not wrapped with brackets, you did not factor it... To pradip actually
2007-03-09 07:12:37 · answer #5 · answered by lastdemocratalive 2 · 0⤊ 1⤋
we know, x^3-y^3=(x-y) (x^2+xy+y^2)
therefore, x^3-y^3/(x-y)=x^2+xy+y^2
2007-03-09 07:10:44 · answer #6 · answered by SS 2 · 1⤊ 1⤋
x2 + xy + y2 =0
(x+y)(x+y)=0
2007-03-09 07:08:36 · answer #7 · answered by Leigh K 3 · 0⤊ 4⤋
can factor only with complex roots ( DELTA is negative).
2007-03-09 07:12:40 · answer #8 · answered by Wally H 2 · 0⤊ 1⤋
Answer: unfactorable...
2007-03-09 08:04:31 · answer #9 · answered by kadablue 1 · 0⤊ 0⤋
(x+y)(x+y)
2007-03-09 07:06:55 · answer #10 · answered by samantha.swan 2 · 0⤊ 4⤋