Math Help Please?

Question

The classroom is 27 feet long, 20 feet wide and 10 feet high.

A basketball has a diameter of 9 inches.

Find out how many basketballs fit into this classroom?

Answer 1

The answer is 42

Answer 2

Basketball is 3/4 feet in diameter.
Therefore, you can fit 27 / (3/4) = 27 * 4 / 3 basketballs along the length.
Similarly, you can fit 20 * 4 / 3 basketballs along the width
and also 10 * 4 / 3 basketballs along the height.

Total number of basketballs =

(27 * 4 / 3) * (20 * 4 / 3) * (10 * 4 / 3) = 12,800

But, of course, this does not work, because you cannot have
fractions of a basketball (note that 20 * 4 / 3 = 26+2/3 and
10 * 4 / 3 = 13+1/3).
If you take away the fractions, you could fit
(27 * 4 / 3) * (26) * (13) = 12,168 basketballs,
but how many can you fit into the remaining spaces.
This looks like a very difficult problem!
The difficulty is - how are the basketballs arranged? -
nice and neatly, each taking up a volume of (3/4)^3 = 27/64
cubic feet, or not so neatly, with subsequent layers sitting
in the grooves formed by a layer of 4 basketballs.
Or even less neatly than that!
Hmmm! this is looking even more difficult.

Answer 3

You have the area: 27x20x10 feet = 5400 cubic feet.

Convert this to inches by multiplying by 12= 64800 cubic inches.

The diameter of the ball is 9 inches, but it's in 3 dimensions so the area it will take up is about 9 inches cubed, or 81 cubic inches. Now divide this area into your total cubic inches available.
64800/81= 800 balls. Unless you have to account for the room left over in the corners. I don't know, I hope this helps, because I have been up very late. And could be completely delirious.

Answer 4

Volume of the class room=5400 feet
Volume of a basketball = 381.9 inches
Number of basketballs in the classroom= (volume of the class room)/(volume of a basketball)

Answer 5

Are you asking this question because you didnt do your homework. Shame on you