boxes that are 8 in tall are stacked next to boxe that are 15in tall. find the least number of each size box that could be stacked next to each other that both stacks are the same hieght
2007-03-08 22:29:24 · 3 answers · asked by ally 2 in Science & Mathematics ➔ Mathematics
Since 8 and 15 are relatively prime, the 'least common multiple' of them is 8*15 = 120 so you would need 8 of the 15" boxes and 15 of the 8" boxes and each stack would be 120" tall.
HTH ☺
Doug
2007-03-08 22:36:46 · answer #1 · answered by doug_donaghue 7 · 1⤊ 0⤋
you would need 5 of the 8 in tall boxes and 3 of the 15 in tall boxes
2007-03-09 06:37:37 · answer #2 · answered by Morganna 5 · 0⤊ 0⤋
you should find l.cm(least common multiple) of 8 and 15 , which is :
[8,15] = 120 , so
15 boxes of 8" tall are as high as 8 boxes of 15" tall.
2007-03-09 06:43:25 · answer #3 · answered by Kiamehr 3 · 1⤊ 0⤋