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Suppose 12.0g of carbon (C) reacts with 70.0g of sulfer (S) to give 76.0g of the compound carbon disulfide (CS2). in this process, all the carbon gets used up, but some elemental sulfer is left over.

a) for the law of conservation of matter to be obeyed, how much sulfer is unused?

b) What is the percent C in CS2?

c) What is the percent S in CS2?

d) what is the sum of the %C and %S in CS2?

2007-03-08 18:46:46 · 2 answers · asked by melia_bg 1 in Science & Mathematics Chemistry

2 answers

a)moles of sulphur used = 1.9983348mol
moles of sulphur left = 0.1854954mol
mass of sulphur unused = 32.066g/mol *0.1854954mol = 5.9480955g


b) 15.77%

c) 84.23

d) 15.77 + 84.23 =100%

2007-03-08 19:06:39 · answer #1 · answered by boago d 2 · 0 0

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2016-10-17 22:40:38 · answer #2 · answered by ? 4 · 0 0

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