Calculate the mass, in grams, of 9.3 X 10^22 molecules of nitrous oxide, N2O?

Answer 1

Recall that Avogadro's number gives us the relationship that one mole of anything is 6.02 x 10^23. So, one mole of N20 molecules is 6.02 x 10^23 molecules.

What we know:
We have 9.3 x 10^22 molecules of N2O

The Molecular Weight of N is 14 g/mole
The Molecular Weight of O is 16 g/mole

Therefore, the Molecular Weight of N20 is 44 g/mole (2 x 14 g/mole N + 1 x 16 g/mole O)

What do we want? Mass of N2O

9.3 x 10^22 molecules N2O x (1 mole N2O / 6.02 x 10^23 molecules N2O) x (44 g N2O / 1 mole N2O) = 6.8 g N2O

Answer 2

Ok.
N = 14g/mole
O = 16g/mole
For N2O, you´ll get the Average Molecular Weight of 44g/mole.
By multiplying the AMW of N2O(44g/mole) to the given 9.3x10^22 molecules, you can get the answer in grams.

44g/mole
x
9.3x10^22molecules
_______________
409.2x10^22 grams > the mass of Nitrous Oxide

Answer 3

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