directly to the airport?
2007-03-08 16:43:34 · 7 answers · asked by roflroflrofl123 3 in Science & Mathematics ➔ Mathematics
Tan inverse of (1.6) south of west
2007-03-08 16:51:51 · answer #1 · answered by Shrey G 3 · 1⤊ 0⤋
Draw a picture. From the picture, what we are looking for is the bearing that will take the plane 160 miles south in the same time it goes 100 miles west. The plane will be flying west of south, with the angle being Tan-1(100/160), the angle for which the tangent is 5/8, which can be found from the calculator or a table.
2007-03-08 16:51:34 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
Make diagram such that :-
Aircraft is at C
B is 160 miles due south of C
Airport (A) is 100 km due west of B
angle ACB = tan ^(-1) 100 / 160 = 32°
Bearing of A from C is 180° + 32° = 212°
2007-03-08 22:06:01 · answer #3 · answered by Como 7 · 0⤊ 0⤋
The direction to get back to the airport is South West as it is North East of the airport.
Hope this helps.
2007-03-08 16:52:58 · answer #4 · answered by Anonymous · 0⤊ 0⤋
arctan(160/100) gives you the angle north of east outbound from the airport. which is an angle of 58 degrees above the positive x axis. So inbound, you'd be the opposite of that. 58 degrees south of east, or in aviation: Heading 212
Let me try to remember from my Air Traffic control days... I believe the saying is "course to, bearing from." So the bearing would be tracking inbound on the 032 radial.
2007-03-08 16:48:23 · answer #5 · answered by Anonymous · 0⤊ 0⤋
tan(B - 180) = 100/160 = 5/8
B - 180 = 32.00
B = 212°
2007-03-08 17:12:02 · answer #6 · answered by Helmut 7 · 0⤊ 0⤋
tan^-1(16/10) = 58 deg==> S58W
2007-03-08 16:51:58 · answer #7 · answered by DuckyWucky 3 · 0⤊ 0⤋