what is the least positive integer x such that x^2 is greater than or equal to 95?

1 ⤊

can someone please explain to me how to do this problem?
thanx

2007-03-08 16:39:16 · 3 answers · asked by jorie715 2 in Science & Mathematics ➔ Mathematics

x^2>=95
The smallest perfect square greater than 95 is 100
Therefore
x^2=100
x=10

2007-03-08 16:42:12 · answer #1 · answered by Shrey G 3 · 1⤊ 0⤋

x^2 â¥ 95
9^2 = 81 < 95
10^2 = 100 > 95
There is no positive integer smaller than 10 which fits the condition.

2007-03-09 00:51:42 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋

10 is your answer.

9^2 = 81
10^2 = 100

Least positive Integer => 100 when squared is 10.

2007-03-09 00:42:08 · answer #3 · answered by kevin_l_robinson 1 · 0⤊ 0⤋