z^4 y/z^5 y^3
2007-03-08 16:13:49 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
=1/zy^2
=z^(-1)y^(-2)
2007-03-08 16:16:47 · answer #1 · answered by Maths Rocks 4 · 0⤊ 0⤋
What's the problem? If you have a^n/a^m, this simplies to a^(n-m). For example, with the z-terms, z^4/z^5 = z^-1 or 1/z. y/y^3 = y^-2 or 1/y^2.
Multiplying these two, the simplified form is
1/(zy^2)
2007-03-09 00:19:34 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
z^4 y over z^5 y³ = 1 over zy²
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2007-03-09 00:31:25 · answer #3 · answered by aeiou 7 · 0⤊ 0⤋
um..i think it is: 1/zy^2 ... the numerator z^4 cancels out, leaving z in the denominator. the y in the numerator cancels out, leaving y^2 in the denominator
2007-03-09 00:17:08 · answer #4 · answered by Arinadi 2 · 0⤊ 0⤋
y^4/z, but make it clearer next time.
2007-03-09 00:16:56 · answer #5 · answered by Anonymous · 0⤊ 1⤋