I'm stuck on a problem for BC calc, and I don't think my logic is sound...could anyone look over this and see if it makes sense at all?
Problem: Show that the improper integral: 0 ~ infinity (e^-x / square root x ) dx converges.
I broke it up into two parts:
Integral of 0 ~ infinity (1 / e^x) dx converges to 1,
Integral of 0~ infinity (1 / square root x) diverges to infinity.
So I said that since the integral e^-x converges to 1 and the integral of 1 / square root x diverges to infinity, the result was 1 / infinity, which would be 0, thus converging the original function to 0.
Does this make sense at all? It seems odd that an integral would reach 0...
2007-03-08
16:02:02
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3 answers
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asked by
Moosehead
2
in
Science & Mathematics
➔ Mathematics