math geniuses!!pls help me!!?

Question

find the slope-intercept form of the line passing through the point (7,1) and parallel o the line -2(x) + 7y = -4

Answer 1

First, rewrite the equation of the given line in slope-intercept form:

-2x+7y=-4
7y=2x-4
y=2x/7-4/7

So the slope of the line is then 2/7. Thus the line you are looking for will be of the form y=2x/7+C. Since this line passes through (7, 1), we know that will be a solution to this equation, so plugging it in, we may solve for C:

y=2x/7+C
1=2(7)/7+C
1=2+C
-1=C

So C=-1, and the equation of the line is then y=2x/7-1

Answer 2

The desired equation is: y = (2/7)x - 1.

It is found as follows:

If a line is parallel to another one, you can first simply take over its form as far as x and y are concerned, and evaluate what that gives at the point it has to pass through. (### --- See footnote.) So:

-2(x) + 7y = -14 + 7 = - 7 (### --- see footnote) and therefore:

7y = 2x - 7 (that checks!), or, in the slope-intercept form desired:

y = (2/7)x - 1.

So: the slope is 2/7, and the y-intercept is - 1.

Live long and prosper.

FOOTNOTES:

### 1. By doing this evaluation immediately, one avoids Pascal's unnecessary step of introducing an equation with an unknown ' C ' in it and then solving for that C. It's quicker to simply evaluate it in the way I did.

2. 'Maths Rocks' (immediately below) has the wrong sign for the ' x ' term, hence his different (and incorrect) result, as well as not giving it in the form requested.

Answer 3

7y= -4+2x
y= 2x/7 -4/7
gradient of parallel line
= 2/7
y-1= 2/7 (x-7)
7y-7= 2x -14
2x+7y= 7

Answer 4

transcript the equation
y=(2/7)x-(4/7)
then slope is =2/7

1=2/7*7+n

the 'n' is the intercept you must solve the simple equation