math geniuses!! pls help me!!?

Question

give the standard form of the equation of the line that is perpendicular to y= -1/3(x) - 2 and contains (-5,-3).

Answer 1

Line perpendicular to y=-1/3 x -2
m (-1/3) = -1
m = 3

The line : y = 3x + C
The line contains (-5,-3)
-3 = 3(-5) + C
C = 12

So, y = 3x + 12

Answer 2

First, note that the standard form of a linear equation is Ax + By = C. The equation we are given is in slope-intercept form (slope is -1/3, intercept is -2). A line perpendicular would have a slope that is the negative reciprocal of the given one (3). We can use the last form of a linear equation, point slope, to get
y - (-3) = 3 (x - (-5)) -> y + 3 = 3 (x + 5) -> y + 3 = 3x + 15
The standard form is:
y - 3x = 12

Answer 3

First you have to know that perpendicular lines have slopes that are the negative reciprocal of each other...

So in your equation, y = -1/3x - 2 .. the slope is -1/3

The negative reciprocal is +3/1 or +3.

Using point slope form ...

y - -3 = +3 (x - -5)

Now you have to combine some signs ..

y + 3 = 3 (x + 5)

You can leave it like that if you want, however, I am guessing your teachers wants it in slope/intercept form like the original equation ... so ...

y + 3 = 3x + 15 .... distributed on the right side
y = 3x + 12 .......... subtracted 3 from both sides.

All Done!

Answer 4

Principle: If m is the slope of a line, a line perpendicular to it has a slope of -(1/m). Since the given line is in slope-intercept form, the desired line has a slope 3. That line is
y= 3x + b, where b is to be found from the point data. That data substituted in gives -3 = 3(-5)+b
So b= 12. Since we want STANDARD form, we push things around to 3x - y +12 = 0

Answer 5

Perpendicular lines have opposite, reciprocal slopes. So the slope of the line you want is 3. In point-slope form, the line is:

y + 3 = 3(x + 5)

In standard form, the line is:

y + 3 = 3x + 15
-3x + y = 12 <-----------standard form

In slope-intercept form, the equation is:

y = 3x + 12

Answer 6

2 lines are perpendiculars when m1*m2=-1
m1=-1/3 so m2 =-1/(-1/3)=>m2=3
so the ecuation of line
y=3x+a and contain (-5,-3)
=>-3=3*(-5)+a
=>-3=-15+a=>
a=12
line is
y=3x+12

Answer 7

y = -1/3 x - 2 (-5, -3)
y=mx+b
-3 = 3 (-5) -b
b=12
y = 3x + 12
3x - y = -12