A-B=C,D/E=F,G+H=I,CxF=I letter represent different digit from 0 to 9 .find the values of above letter?

Question

placement question,so please help me

Answer 1

ok think it out
if C*F=I then neither C nor F cant be 1, and I cant be 1,2,3,4,5,7,or9 so it has to be 6 or 8 which in turn means that C and F can only be 2, 3, or 4
C cant be 2 because then you cant do D/E and get to 3 or 4 so 9-5=4, 6/3=2, 7+1=8, 4*2=8 so A=9 B=5 C=4 D=6 E=3 F=2 G=7 H=1 and I=8

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Answer 2

since all number should be Integer, D/E has to be even number. So if D=4 and E=2, then F=2, which is not correct as D is not equal to F.

So again, D=6, E=3 makes F=2.

Now, G+H=I and C*F=I.

So, (G+H)=C*F
i.e. (G+H)=C*2 (Subsituting value for F).

Apply the same logic C has to be Integer. So G and H should be odd so the addition will make the sum even and didivng it by 2 will give even result.

Using elimination Theory, assume G =1 so H cannot be 3 (as E=3) also it cannot be 5 as the result will be 3. (because E=3). So lets assume H=7.

Applying these values (G+H)/2=C give C=4.

So G=1, H=7 and C=4. Since G+h =I, I = 8.

A-B=C. Since C > 0, B < A. So A=9, B=5.

Summary. A=9, B=5, C=4, D=6, E=3, F= 2, G = 1, H = 7, I = 8