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If the first digit cannot be a 0, how many account numbers are possible?

A - 80,000,000
B - 9,000,000
C - 8,000,000
D - 1,000,000

Please explain your answer or explain to me how to start this problem. Thank You.

2007-03-08 15:09:28 · 2 answers · asked by Dan 3 in Science & Mathematics Mathematics

2 answers

9*10^6, or 9,000,000. this is so because the first digit can be 1-9, which is 9 numbers. the second, third, through seventh digit can be 0-9, or 10 choices. multiply together because these are independent events(first number does not dictate what subsequent numbers will be) to get the answer.

2007-03-08 15:14:05 · answer #1 · answered by metalluka 3 · 0 0

The answer is B, because you have 10,000,000 combinations in a seven digit number assuming you can use all the numerals from 0 to 9. Since 0 cannot be the first digit, subtract 1 M from 10 M and you'll get 9,000,000.

2007-03-08 16:30:51 · answer #2 · answered by kabitenyong kapampangan 1 · 0 0

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