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2y2 + 5y +2 <-- y2 = y squared.
and
2y2+7y+3

2007-03-08 14:29:58 · 3 answers · asked by dorkified at heart 1 in Science & Mathematics Mathematics

3 answers

(2y+1)(y+2) = 2y^2 + 5y + 2

(2y+1)(y+3) = 2y^2 + 7y + 3

2007-03-08 14:35:39 · answer #1 · answered by JH 2 · 0 0

(2y + 1)(y + 1) = 2y2 + 5y + 2

(2y2+7y+3) = (2y + 1)(y + 3)

2007-03-08 14:32:53 · answer #2 · answered by metalluka 3 · 0 0

(2y+1)(y+2)



(2y+1)(y+3)

2007-03-08 14:33:31 · answer #3 · answered by leo 6 · 0 0

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