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And also how to make this expression true with parentheses
-3*25-2*-5 to the 2 power divided by 5 = -25

2007-03-08 14:20:59 · 6 answers · asked by Tiffany W 1 in Science & Mathematics Mathematics

6 answers

27^(2/3)
= (3^3)^(2/3)
= 3^(3*2/3)
= 3^2
= 9

I can't make out what the second one's supposed to be.

2007-03-08 14:27:13 · answer #1 · answered by Engineer-Poet 7 · 0 0

3^3 =27, so 27^(1/3) = 3, then 3^2 = 9. Therefore, 27^(2/3) = 9

For the second expression you want something (x) divided by 5 = -25, so x = 5 * -25 = -125

so - (3 * 25) - (2 * (-5)^2) = -125

2007-03-08 22:43:14 · answer #2 · answered by TF 1 · 0 1

1) 27²/³ = ³\/27² =
Eliminating radical:
³\/(3³)² = 3² = 9
<>
2)
(-3*25)-(2*-5²) divided by 5 = -25
(-75 -2 * 25) : 5 = -25
(-75 - 50) : 5 = -25
-125 : 5 = -25
>><<

2007-03-08 22:28:05 · answer #3 · answered by aeiou 7 · 0 0

Simplify by converting 27 to 3^3 first;

then 27^2/3 = 3^(3*2/3) = 3^2 = 9.

2007-03-08 22:39:35 · answer #4 · answered by PJA 4 · 0 1

The second question is impossible because no matter what the answer is, once you square it, it will be positive and there is no way to get a -25 by dividing by 5

2007-03-08 22:30:20 · answer #5 · answered by TikiKey 1 · 0 0

9 ppl =D

2013-10-24 21:44:50 · answer #6 · answered by Emily Enriquez 1 · 0 0

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