Use the numbers 1,2,3 and 4 with any operation to make an expression that equals 15-25?

Question

put equation =15

put equation =16

put equation =17

put equation =18

put equation =19

put equation =20

put equation =21

put equation =22

put equation =23

put equation =24

put equation =25

put equation =15

put equation =16

put equation =17

put equation =18

put equation =19

put equation =20

put equation =21

put equation =22

put equation =23

put equation =24

put equation =25

you can only use those number once ...

thanks R.S for reminding me

Answer 1

There r a lot many solutions. However i choose to give this set that greatly relies on exponents and factorials.
15 = 4! - 3! - 2! - 1!
16 = 4! - 3! - (2! / 1!) = 4^2^1^3 (remember exponentiation operator is evaluated from the rightmost one)
17 = 4! - 3! - 2! + 1!
18 = 4! - 3!/(1!^2!)
19 = 4! - 3! + 2! - 1!
20 = 4! - 3! + (2!^1!)
21 = 4! - 3! + 2! + 1!
22 = 4! - 3!/2! + 1!
23 = 4! - 3 + (2!/1!)
24 = (4!)^1^2^3
25 = 4! + 3!/(1+2)!
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

(2+a million/2+a million)2+a million(3-4)=2+a million 5c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc(-2+a million)=2+a million 2+a million-2+a million=2+a million 2+a million=2+a million (2+a million-4)5c93e584b16c9b9ceb339d8ca8395cc35c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc=2+a million (-3)5c93e584b16c9b9ceb339d8ca8395cc35c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc=2+a million 05c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc=2+a million 2+a million=2+a million 2+a million*5c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc4 -3=3 5c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc=3 3=3 4 -(3-[5c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc])=4 4 -(3-3)=4 4 -0=4 4=4 (4/5c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc3)/2+a million=5 (5c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc3)/2+a million=5 5/2+a million=5 5=5 4/5c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc35c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc=6 5c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc35c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc=6 55c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc=6 6=6 2+a million^45c93e584b16c9b9ceb339d8ca8395cc(2+a million*3)=7 5c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc6=7 7=7 2+a million^5c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc(35c93e584b16c9b9ceb339d8ca8395cc4)=8 5c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc7=8 8=8 2+a million*5c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc45c93e584b16c9b9ceb339d8ca8395cc3=9 5c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc45c93e584b16c9b9ceb339d8ca8395cc3=9 65c93e584b16c9b9ceb339d8ca8395cc3=9 9=9 3*4 -2+a million*2+a million=5c93e584b16c9b9ceb339d8ca8395cc0 5c93e584b16c9b9ceb339d8ca8395cc5c93e584b16c9b9ceb339d8ca8395cc-2+a million=5c93e584b16c9b9ceb339d8ca8395cc0 5c93e584b16c9b9ceb339d8ca8395cc0=5c93e584b16c9b9ceb339d8ca8395cc0

Answer 3

(4*4)+3+2=21
3+4+4+4+2-1=16
or did you mean that we can use each number once in an equation?...cuz so far this seems a little too easy