7x^2 - 7x + 1 = 0
If there is more than one solution than write them all
2007-03-08 14:18:58 · 5 answers · asked by Help please 1 in Science & Mathematics ➔ Mathematics
x = [7 +/- sqrt(49 - 4*7)]/14
= [7 +/- sqrt(21)]/14
2007-03-08 14:22:56 · answer #1 · answered by metalluka 3 · 0⤊ 0⤋
a = 7, b = -7, c = 1
x = [7 +/- sqrt(49 - 4(7))]/14
x = [7 +/- sqrt(21)]14
x = 1/2 +/- sqrt(21)/14
2007-03-08 22:23:11 · answer #2 · answered by Anonymous · 0⤊ 0⤋
a = 7
b = -7
c = 1
x = ( -b ± âb² - 4ac ) / 2a
x = ( -(-7) ± â(-7)² - 4(7)(1) ) / 2(7)
x = ( 7 ± â21 ) / 14
x = ½ ± â21 / 14
2007-03-08 22:26:27 · answer #3 · answered by novangelis 7 · 0⤊ 0⤋
[7+-sqrt(49-28)]/14
equals [7+-sqrt(21)]/14
2007-03-08 22:23:29 · answer #4 · answered by bruinfan 7 · 0⤊ 0⤋
7+-49-28/14
7+-4.58/14
7+4.58/14=0.83
7-4.58/14=0.17
Solutions are={0.83,0.17}
2007-03-08 22:41:48 · answer #5 · answered by Micky [momo]♥ 2 · 0⤊ 0⤋